10s^2+37s-12=3

Solution for 10s^2+37s-12=3 equation:

10s^2+37s-12=3

We move all terms to the left:

10s^2+37s-12-(3)=0

We add all the numbers together, and all the variables

10s^2+37s-15=0

a = 10; b = 37; c = -15;
Δ = b2-4ac
Δ = 372-4·10·(-15)
Δ = 1969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{1969}}{2*10}=\frac{-37-\sqrt{1969}}{20}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{1969}}{2*10}=\frac{-37+\sqrt{1969}}{20}
$